//解决js混合运算精度偏失问题
export const count = {
	//加
	add(arg1, arg2) {
		arg1 = arg1 || '0'
		arg2 = arg2 || '0'
		var r1, r2, m, c;
		try {
			r1 = arg1.toString().split(".")[1].length;
		}catch (e) {
			r1 = 0;
		}
		try {
			r2 = arg2.toString().split(".")[1].length;
		}catch (e) {
			r2 = 0;
		}
		c = Math.abs(r1 - r2); //位数差的绝对值
		m = Math.pow(10, Math.max(r1, r2)); //较大数的幂
		if (c > 0) { //位数相差
			var cm = Math.pow(10, c);
		if (r1 > r2) {
			arg1 = Number(arg1.toString().replace(".", "")); //转化成数字
			arg2 = Number(arg2.toString().replace(".", "")) * cm;
		} else {
			arg1 = Number(arg1.toString().replace(".", "")) * cm;
			arg2 = Number(arg2.toString().replace(".", ""));
		}
		} else { //位数相等
			arg1 = Number(arg1.toString().replace(".", ""));
			arg2 = Number(arg2.toString().replace(".", ""));
		}
		return (arg1 + arg2) / m;
	},
	//减
	sub(arg1, arg2) {
		arg1 = arg1 || '0'
		arg2 = arg2 || '0'
		var r1, r2, m, n;
		try {
			r1 = arg1.toString().split(".")[1].length;
		}catch (e) {
			r1 = 0;
		}
		try {
			r2 = arg2.toString().split(".")[1].length;
		}catch (e) {
			r2 = 0;
		}
		m = Math.pow(10, Math.max(r1, r2)); //last modify by deeka //动态控制精度长度
		n = (r1 >= r2) ? r1 : r2; //取位数大的
		// n = Math.max(r1, r2);
		return ((arg1 * m - arg2 * m) / m).toFixed(n);
	},
	//乘
	mul(arg1, arg2) { //去小数点扩大后，再除以相应倍数
		arg1 = arg1 || '0'
		arg2 = arg2 || '0'
		var m = 0, s1 = arg1.toString(), s2 = arg2.toString();
		try {
			m += s1.split(".")[1].length;
		}catch (e) {
		}
		try {
			m += s2.split(".")[1].length;
		}catch (e) {
		}
		return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m);
	},
	//除
	div(arg1, arg2) { //去小数点，扩大倍数，再乘以相应倍数
		arg1 = arg1 || '0'
		arg2 = arg2 || '0'
		var t1 = 0, t2 = 0, r1, r2;
		try {
			t1 = arg1.toString().split(".")[1].length;
		}catch (e) {
		}
		try {
			t2 = arg2.toString().split(".")[1].length;
		}catch (e) {
		}
		r1 = Number(arg1.toString().replace(".", ""));
		r2 = Number(arg2.toString().replace(".", ""));
		return (r1 / r2) * Math.pow(10, t2 - t1);
	}
}